Holidays Homework (June 22 - 26)

Dear P6D and 6F pupils,

As there is no supplementary on 22 and 23 June, please complete the sample PSLE paper found at the back section of the PSLE booklet.

I will post the answers within the next few days for the beginning sections.

Mdm Goh

Percentage (Practice 1) - Qn 32 - 46

These answers are taken from Tan Zi Hua (6F). Thanks to her for her neat and accurate workings.

Revision Paper (Term 1) - Booklet B

(Thanks to Lee Xin Yee (6D) for the neat and systematic answers)

Qn 16 - 17




Qn 18 - 19

Qn 20 - 22

Qn 23 24

Qn 25

Qn 28-19

Qn 30

Qn 31 - 33 ( no need to do corrections)

Qn 34 - 35

No. of Groups No of children in each group Total (must be 36)

1 36 (not in the ans as should be more than 1 gp)

2 18 (Yes)

3 12 (Yes)

4 9 (Yes)

6 6 (Yes)

9 4 (Yes)

12 3 (Yes)

18 2 (Yes)

36 1 (not in the ans as should be fewer than 36 grps)

Hence, the total no. of way = 7 ways

Qn 37 - 38

Men - 4 units

women - 5 units

Women 5 5

--------- = ____ = _____

Guests 4+5 9

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Qn 39

Qn 40

Qn 41

Book cost $5.50 more than a file.

File - 1 unit

Book - 1 unit + 5.50

1 book and 4 files

Book - 1 unit + 5.50

4 files - 4 units

Total : 5 units + 5.50 = 13

5 units = 13- 5.50 = 7.50

1 unit = 7.50 ÷ 5 = 1.50

File = 1 unit ===> $1.50

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Qn 42

Monday - sold 3/5

Total muffins made - 5 units

________________________________

<-----Mon-----------------> <-----Left------>

Tuesday - 1/4 of the remainder

-> remainder is 2 units.

-> cut each unit into half

-> do the same for the other 3 units

-> Hence, Tuesday : 1 part.

Monday - more than tues by 250

- Monday : 6 parts

- Tuesday : 1 part

Monday more by 5 parts => 250

1 part => 250 ÷ 5 = 50

left : 3 parts => 50 x 3 = 150 muffins

===============================

Qn 43

Last Year

Boys : 1 unit

Girls : 2 units

TOTAL : 3 units

This year

Boys : 1 unit x 4 times = 4 units

Girls : 2 units x 3 times = 6 units

Total : 4 + 6 = 10 units

10 units - 3 units = 7 units (joined)

7 units => 70

1 unit => 10

3 units => 10 x 3 = 30 members (last year)

====================================

Qn 44

Joel and Simon had the same amt of money. After Simon gave to Joel, note that the total still remains the same.

Hence, the total for before and after model is the same.

Before (EACH HAS THE SAME)

Joel : 26 ÷ 2 = 13 units

Simon : 26 ÷ 2 = 13 units

(Total : 26 units)

After

Joel : 8 units x 2 = 16 units

Simon : 5 units x 2 = 10 units

(note : 13 units cannot be divided into 2, will change the total to 26 units)

Total : 13 units x 2 = 26 units

Joel : 16 units - 13 units = 3 units (extra - received from Simon)

3 units = $15

1 unit = $15 ÷ 3 = $5

(Joel) 16 units = $5 x 16 = $80

==================================

Qn 45 -50

- I will explain in class :)

SA1 Practice 1 (Booklet A)

Qn 1 & Qn 2















(3)






(4)





















Qn 3 and 4
























































Qn 5 and 6




































































Qn 7 and 8





















































Qn 9















































Qn 10















































Qn 11


















































Qn 12


















































Qn 13 - The question is wrong. It should be "decrease" instead of increase.








Qn 14

(3)

Qn 15

Qn 16 and 17

Qn 18

Qn 19 and 20

Qn 21

Solution:

7u -> $ 70y

1 u -> $10y

12u -> $10y x 12 = $120y

Qn 22 and 23

Qn 24

Qn 25

Solution

Amt to be paid

At 2.45 pm -> $2

At 3.15 pm -> $2 + 1.50 =3.50

At 3.45 pm -> $3.50 + 1.50 = $5

At 4.15 pm -> $5.00 + 1.50 = $6.50

Time left carpark : 4.15 pm

Qn 26 and 27

Qn 28

Qn 29

Qn 30

Qn 31

Qn 32

Qn 33

Qn 34

Qn 35

Announcement for 6D and 6F pupils

Dear pupils,

It is ok if you can't finish the corrections. I am trying my best to upload the solutions.

Just do corrections for whatever I have uploaded.

In the meantime, you can attempt the SA1 practice (Booklet B)

Sorry to keep you waiting. :)

Mdm Goh.

Term 1 (Term Test) - Booklet A

Question 1

Given 75.6 ÷ 6 = 12.6,

75.6 ÷ 60 = 75.6 ÷ 6 ÷ 10

= 12.6 ÷ 10
= 1.26



Ans (3)

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Question 2

25 431.89
2- Ten thousands place
5- Thousands place
3- Tens place
1- Ones place
8- Tenths place
9- Hundredths place

Ans (1)

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Question 3
Ans (2) - 450
_____________________________________

Question 4

Convert the mixed number to improper fraction (in quarters)

10/4 = 10 quarters
Ans (1) - 10

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Question 5

Ans (2) 4 351 000

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Question 6

Perimeter = outline = sum of the 3 sides

Step 1 : Find length AB (H)

Area of triangle = 1/2 x B x H
96 = 1/2 x 16 x H
96 = 8 x H
H = 96 ÷ 8 = 12


Step 2 : Find the perimeter

Perimeter = 16 + 20 + 12 = 48 cm

Ans (3)

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Question 7

(Draw the trees - to visualise the number of intervals)


Distance bet 1st and 4th tree = 3 units

3 units => 24 m
1 unit => 24 ÷ 3 = 8 m


Distance between 1st and 10th tree = 9 intervals = 9 units

9 units => 9 x 8 = 72 m

Ans (1)

------------------------------------

Question 8

Ans (2)

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Question 9

Ahmad 7 units

Benny 3 units

Total - 10 units -> 30 years
1 unit -> 30 ÷ 10 years = 3 years
7 units -> 3 x 7 = 21 years old

Ans (4)


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Question 10

Area of BCD = 1/2 x B x H

= 1/2 x BC x AD

= 1/2 x 5 x 5

= 12.5

Ans (1)

---------------------------------------------

Question 11

2 eggs --> 80 g of flour

1 egg --> 80g ÷ 2 = 40g of flour

7 eggs --> 40g x 7 = 280 g of flour

Ans (3)

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Question 12

(8m + 3 - 3m) ÷ 3

= (8m - 3m + 3) ÷ 3

= (5m +3) ÷ 3

= (5m+3)

3

Ans (3)

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Question 13

Step 1 : Find the height (Line AB) of triangle AXC

Area of ABC = 1/2 x B x H

80 = 1/2 x BC x AB

80 = 1/2 x (9+7) x AB

80 = 1/2 x 16 x AB

80 = 8 x AB

AB = 80 ÷ 8

= 10cm

Step 2 : Find the area of triangle AXC

Area of AXC = 1/2 x B x H

= 1/2 x (XC) x (AB)

= 1/2 x 9 x 10

= 1/2 x 90

= 45

Ans (3)

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Question 15

James 6 units

Son 1 unit

Daughter => 1 unit - 2 years

Solution :

James : 6 units --> b years old

Son : 1 unit --> b ÷ 6 = b/6 years old

Daughter : 1 unit - 2 years = b/6 - 2

Ans (3)

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Question 16

8w + 10 + 2 w - 7

= 8w + 2w + 10 - 7

= 10w + 10 - 7

= 10w +3

---------------------------------------------

Question 17

3y + 21 - 6y (y = 7)

= 3 x y + 21 - 6 x y

= 3 x 7 + 21 - 6 x 7

= 21 + 21 - 42

= 42 - 42

= 0

---------------------------------------------

Question 18

6 + 2 = 8

Ans : 8 faces

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Question 19

30 + 7 x 20 - 200 ÷ 5

= 30 + 140 - 40

= 170 - 140

= 130

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Question 20

Two digit number = AB (less than 70)

Sum of my digits = A + B = 9

Divisible by 7 --> means the number is a multiple of 7

Step 1 : List out all the multiples of 7 that are less than 70 and their respective sum of the digits

Multiples of 7 (AB) Sum of digits (= 9?)

14 1 + 4 = 5 (Not the ans)

21 2 + 1 = 3 (not the ans)

28 2 + 8 = 10 (not the ans)

35 3 + 5 = 8 (not the ans)

42 4 + 2 = 6 (not the ans)

49 4 + 9 = 13 (not the ans)

56 5 + 6 = 11 (not the ans)

63 6 + 3 = 9 (YES ! meet all conditions)

Ans: The number is 63.

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Question 21

From the diagram,

12 units (interval) => 1.2m = 120cm

1 unit => 120 ÷ 12 = 10cm

Shaded rectangle : 7 units => 10 x 7 = 70 cm

Ans : 70 cm

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Question 22

(Note : qn require you to answer in litre)

Convert 750ml to litre

750ml = 0.750 litre

Volume of the drink = 750ml + 1.5 litre

= 0.75 +1.5 litre

= 2.25 litre.

Ans : 2.25 litre

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Question 23

(Make sure that the units are the same)

Ratio : 60 cents : $10.20

= 60 cents : 1020 cents

= 60 : 1020

= 6 : 102

= 1 : 17

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Question 24

Total units to make the paint (2Litres) = 5 + 3 + 2 = 10 units

10 units ==> 2 litres

1 unit ==> 2 ÷ 10 = 0.2 litres

5 units (Blue) ==> 0.2 x 5 litres = 1 litre

Ans : 1 litre

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Question 25

Joe has 3/4 as many stickers as David :

Joe 3 units

David 4 units

Joe gave 1/2 to David : Joe have 3 units, we have to change it to 6 units so that we can divide total into 2 easily.

New ratio:

Joe 6 units

David 8 units

After :

Joe 6 x 1/2 = 3 units (left 1/2)

David 8 units + 3 units (from Joe) = 11 units

Joe : David

Ans - 3 : 11

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Question 26

Cheryl has 250 stamps.
1 album can contain 184 stamps.
2 albums can contain 184 x 2 = 368 stamps

Extra stamps to fill up 2 albums = 368 - 250 = 118 stamps

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Question 27

Danny - > 48 kg
Brother -> 48 + 14 = 62 kg
Total -> 62 + 48 = 110 kg

Average mass = total ÷ 2
= 110 ÷ 2
= 55 kg

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Question 28

Toy car - $ b
Doll - $ c more than car --> $ c + b

Items

4 Toy Car : b + b + b + b
2 dools : c + b + c + b = 2 c + 2 b

Total : 4 b + 2c + 2b
= 4b + 2b + 2c
= 6b + 2 c

Ans : $ (6b + 2c)

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Question 29

Total ribbon Linda has = 5 metres

1 present -> 3x metres
2 presnts -> 3x x 2 = 6x metres

Amount left : Total - used = ( 5 - 6x ) m

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Question 30

Red 1 unit

Blue 4 units
-----------------------------------
Blue 1 part ----> 1 x 4 = 4 units

Green 3 parts -----> 3 x 4 = 12 units


(Task : Make the no. of units for Blue pens to be the same)
-- common no is 4 : refer to the red working above)


Red : Total

1 : (1 + 4 + 12)

1 : 17

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Question 31

Top : Triangle : 3 equal sides = 3 equal pieces of wire

Bottom : Same as top = 3 equal pieces of wire

Side : 3 edges = 3 equal pieces of wire

Total pieces of wire needed = 3 + 3+ 3 = 9

Each piece (1 edge) = 6cm

9 pieces = 6 x 9 cm = 54 cm

Ans : 54 cm

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Question 32

47.48 = 40 + 7 + ?/25

47.48 = 40 + 7 + 0.48

From the above two,

0.48 = ?/ 25

48/100 = ? / 25

48/100 = 12 / 25

Hence ? = 12
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Question 33

Average = 0.25 litre (each guest) = 1/4 litre

34 guests => 34 x 0.25 litre = 34 x 1/4 = 17/2 = 8.5 litre

Left = Total - used = 15 - 8.5 = 6.5 litre.

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Question 34

Fiona 7 units
Gena 6 units
Helen 15 units

Gena has less than Helen => lesser by 15 - 6 = 9 units

9 units = $72

1 unit = $72 ÷ 9 = $8

Fiona (7 units) => $8 x 7 = $56

---------------------------

Question 35

Lucy : 16 units

Mary : 5 units

Tota : 16 + 5 = 21 units

Sum (21 units) ==> 63 years

1 unit ==> 63 ÷ 21 = 3 years

Mary (5 units) ==> 3 x 5 = 15 years old (NOW)

In 15 years' time ==> 15 + 15 = 30 years old.

Ans 30 years old.

Term 1 (Term Test) - Booklet B

Question 36

Question 37

Question 38

Question 39

Question 40

Question 41

Question 42

Question 43

Question 44 & 45

Question 46

Question 47

Question 48

End of paper

Percentage - Practice 1 (Qn 1-20)

Below are the key answers for the questions. (More difficult ones will be explained in details)

Concept : To convert decimal or fraction to percentage, we multiply the decimal or fraction by 100%)

Please show your workings instead of the final answer.

(Note : The fraction in this answer key are typed using /. Write one number on top of the other in your working. )



Question 1

a) 2/25
b) 1/4
c) 1/2
d) 33/55
e) 1/20
f) 3/20
g) 11/25
h) 39/50

Question 2

a) 0.09
b) o.9
c) 0.15
d) 0.62
e) 3% = 3/100 = 0.03
f) 0.35
g) 0.40
h) 0.86

Question 3

a) 75%
b) 80%
c) 7/8 = 7/8 x 100% = 87.5%
d) 70%
f) 84%
g) 48%
h) 30/75 = 30/75 x 100% = 40%
i) 60/150 = 60/150 x 100% = 40%
j) 180/600 = 180/600 x 100% = 30%


Question 4

a) 0.1 = 0.1 x 100% = 10%
b) 0.01 = 0.01 x 100% = 1%
c) 0.9 = 0.9 x 100% = 90%
d) 8%
e) 75%
f) 0.001 = 0.001 x 100% = 0.1%
g) 0.045 = 0.045 x 100% = 4.5%
h) 0.245 = 0.245 x 100% = 24.5%

Question 5

a) 11.25
b) 702
c) $75
d) 180m
e) 10.5 l
f) 9.6 kg

Question 6

100% - 85% = 15%


Question 7

100% - 45% - 20% = 35%

Question 8

36 / 400 x 100 % = 9%

Question 9

No. passed = 200 - 7 = 193

% passed = 193/200 x 100% = 96.5%


Question 10

% having computers = 320/500 x 100% = 64%


Question 11

a) % of the pupils walk to school = 28/40 x 100% = 70%

b) % of the pupils go to school by bus = 100% - 70% = 30%


Question 12

2/5 = 2/5 x 100% = 40%


Question 13

Amount of money = spent + left

spent 2/5 ---> left 3/5

% of his money left = 3/5 x 100% = 60%


Question 14

% of his stamps that are Malaysia stamps
= 3/5 x 100%
= 60%

Question 15

Total = Singapore stamps + Malaysia stamps

Malaysia stamps => 1 - 3/4 = 1/4 of the total stamps

1/4 = 1/4 x 100% = 25%


Question 16

To find percentage, we express the answer as a fraction first.

Fraction of the cloth used = 75cm / 3m (make the units the same)

= 75 cm / 300 cm

= 1/4

% of the cloth used = 1/4 x 100% = 25%

Question 17

Gold medals = 45 - 22 - 14 = 9

% of the medals that are gold medal = 9/45 x 100% = 20%
Question 18

Maths Drill WS

http://www.math-drills.com

Practice Paper Solution

Hi 6D pupils,

Below are the solutions for Qn 49 and 50 which I have missed out.

Qn 49a



Qn 49b

qn 50

Science

Hero's steam Engine


Newton's cradle


Newton's Cradle (different style)